See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let the radius of the smallest circle be a. We find that the radius of the largest circle is 4 – a and the radius of the second largest circle is 3 – a. Thus, 4 a 3 a 5 a 1      . The radii of the other circles are 3 and 2. The sum of their areas is  9 4 14 E    