The resistivity of a 0.8 M — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

Resistivity () = 5 × 10–3 cm. Molarity (M) = 0.8 M Molar conductivity (M) =  1 × M = 10 1   × . 1000 = 0.25 × 106 = 25 × 104 cm2 mol–1