The active ingredient in aspirin is acetylsalicylic acid. The pH of the solution obtained by dissolving two aspirin tablets (containing 0.36 g of acetylsalicylic acid in each tablet) in 250 ml of wate

Question

The active ingredient in aspirin is acetylsalicylic acid. The pH of the solution obtained by dissolving two aspirin tablets (containing 0.36 g of acetylsalicylic acid in each tablet) in 250 ml of water with Ka = 4.0 * 10^-9 is (log 2 = 0.3)

Prashant Kotian · Accepted Answer

Correct answer: A. Mass = 0.72 g, M = 180 g/mol, n = 4.0*10^-3 mol in 0.25 L = 0.016 M. [H+] = √(Ka*C) = √(4.0*10^-9 * 0.016) = 8.0*10^-6 M. pH = 6 - 3 log 2 = 5.1.

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