See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Either increasing or decreasing part lie in [0, 2]  [0, 1] Then  0 1 y c   or 0 and      2 2 2 1 y x ax b c y a b c         or 0 1 2 2 a b    If a  is root, 2 2 2 0 1 0 b a b c a a a a            ……. (i) 4 2 1 0 a b    1 1 0 2 4 b a a    …….. (ii) From (i) and (ii), 1 2  AITS-FT-III (Paper-1)-PCM(Sol.)-JEE(Advanced)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 15 Sum of roots = 2 1 2 11 2 3 4                  a b p p a a 4 2 1 0 a b    1 11 2 2 4    a 1 2 2 b a         For 0 a  , 1 3 2 4  a  2 3  a For 0 a  , 2 2 3 3    a a a