Compound A reacts with NH4Cl and forms a compound B. Compound B reacts with H2O and excess of CO2 to — JEE Mains Chemistry Past Papers Chemistry Question
Question
Compound A reacts with NH4Cl and forms a compound B. Compound B reacts with H2O and excess of CO2 to form compound C which on passing through or reaction with saturated NaCl solution forms sodium hydrogen carbonate. Compound A, B and C, are respectively. (A) CaCl2, NH , (NH4)2CO3 (B) CaCl2, NH3, NH4HCO3 (C) Ca(OH)2, NH3, NH4HCO3 (D) Ca(OH)2, NH , (NH4)2CO3
Answer: C
💡 Solution & Explanation
Reactions related with Solvay process
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes