According to MO theory the bond orders for O2–2, CO and NO+ respectively, are (A) 1, 3 and 3 (B) 2, — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

Species Molecular Orbital configuration Band order = 2 (Nb – Ba) CO   z y x 2 p 2 p 2 p * s * s * KK       2 (10 – 4) = 3 NO+                * p * p 2 p 2 p p * s s 0 y x y x z 2 * KK 2 (10 – 4) = 3 2 O                      * 2y p * 2x p 2y p 2x p 2z p * s 2 s * KK 2 (10 – 8) = 1