I^-(aq.) + MnO4^-(aq.) -H+- X + Mn^2+(aq.); I^-(aq.) + MnO4^-(aq.) -Neutral or weakly OH-- Y + MnO2; MnO4^-(aq.) + Mn^2+(aq.) -ZnSO4- Z + 4H^+. Products X, Y and Z are respectively :

Question

I^-(aq.) + MnO4^-(aq.) -H+-> X + Mn^2+(aq.); I^-(aq.) + MnO4^-(aq.) -Neutral or weakly OH--> Y + MnO2; MnO4^-(aq.) + Mn^2+(aq.) -ZnSO4-> Z + 4H^+. Products X, Y and Z are respectively :

Prashant Kotian · Accepted Answer

Correct answer: A. Step 1: Identify starting materials: Mercuric sulfide (HgS↓) is an extremely insoluble black precipitate. Step 2: Observe reaction with concentrated sodium sulfide (Na2S): The sulfide ion acts as a strong ligand, coordinating with Hg2+ to form a soluble dithiomercurate(II) complex, [HgS2]2-. Step 3: Because the insoluble precipitate dissolves to form a clear solution of a soluble complex, this is classified as a precipitate dissolution reaction (type B).

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