See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

1 1 1 v u f   3 1 1 25 u 10    u =  50 m and for final position of the object AITS-PT-III-PCM(Sol.)-JEE(Main)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 9 7 1 1 50 u 10    u =  25 m Therefore, the shift in object = 50  25 = 25 m Speed = 25 30 m/s = 3 km/hr