The hybridization of the central atom in ICl2^+ is : — Chemical Bonding Chemistry Question

💡 Solution & Explanation

Step 1: Calculate the steric number of the central Iodine atom in ICl2+: Iodine has 7 valence electrons, minus 1 for the positive charge, leaving 6 electrons. Step 2: Two electrons are used to form single bonds with Chlorine atoms, leaving 4 non-bonding electrons (2 lone pairs). Steric number = 2 bond pairs + 2 lone pairs = 4. Step 3: A steric number of 4 corresponds to sp3 hybridization.