In a compound XY2O4, the oxide ions are arranged in CCP arrangement and cations X are present in oct — Solid State Chemistry Question

💡 Solution & Explanation

In CCP arrangement, number of oxide ($O_2$-) ions = 4. The formula unit has 1 X, 2 Y, and 4 O. Total number of octahedral voids = 4. Since X occupies octahedral voids, it takes up 1 void. Cations Y are split equally: 1 in tetrahedral and 1 in octahedral voids. Thus, total octahedral voids occupied = 1 (by X) + 1 (by Y) = 2 voids. The fraction of octahedral voids occupied is 2/4 = 1/2.