The pH of 0.005 M - solution is (log 2 = 0.3) — Ionic Equilibrium Chemistry Question
Question
The pH of 0.005 M - $NaOH$ solution is (log 2 = 0.3)
Answer: D
💡 Solution & Explanation
$NaOH$ dissociates completely. [OH-] = 5 * 10^-3 M. pOH = -log(5 * 10^-3) = 3 - log 5 = 3 - (1 - log 2) = 2 + 0.3 = 2.3. pH = 14 - 2.3 = 11.7.
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