H3C-CH2-CH(Br)-CH3 undergoes (i) PPh3 (ii) BuLi (iii) CH3-C(=O)-CH2CH3 -> X + Y, then X undergoes (i — AITS & Test Series Chemistry Question

💡 Solution & Explanation

  3 i PPh ii BuLi  C C C Br C C C C C PPh3 C C C O C C C C C C C C C  x    3 3 i RCO H ii PPh /  C C C H3 H5C2 C2H5 CH3  x 2 Br  CH3 C C CH3 H5C2 Br Br C2H5 2 H / Ni CH3 C C CH3 H5C2 H H5C2 H Baeyer 's reagent CH3 C C CH3 H5C2 OH H5C2 OH Optically inactive Optically inactive CH3 C C CH3 Br C2H5 H5C2 Br Racemic mixture C H3 CH3 CH3 C H3  y