What mass of should be dissolved in sufficient water to get 20 m^3 of an aqueous solution of pH, 7.3 — Ionic Equilibrium Chemistry Question
Question
What mass of $NaOH$ should be dissolved in sufficient water to get 20 m^3 of an aqueous solution of pH, 7.3, at 25°C?
Answer: D
💡 Solution & Explanation
pH = 7.3 => pOH = 6.7 => total [OH-] = 2.0 * 10^-7 M. Accounting for water's contribution: [$NaOH$] = 1.5 * 10^-7 M. Moles = 1.5 * 10^-7 * 20000 = 3.0 * 10^-3 mol. Mass = 3.0 * 10^-3 * 40 = 0.12 g.
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