Consider the following reactions. PbCl2 + K2CrO4 A + 2KCl (Hot solution) A + NaOH B + Na2CrO4 PbSO4 — JEE Mains Chemistry Past Papers Chemistry Question
Question
Consider the following reactions. PbCl2 + K2CrO4 A + 2KCl (Hot solution) A + NaOH B + Na2CrO4 PbSO4 + 4CH3COONH4 (NH4)2SO4 + X In the above reactions, A, B and X are respectively. (A) Na2[Pb(OH)2],PbCrO4 and (NH4)2[Pb(CH3COO)4] (B) PbCrO4, Na2[Pb(OH)4] and [Pb(NH3)4]SO4 (C) Na2[Pb(OH)2], PbCrO4 and [Pb(NH3)4]SO4 (D) PbCrO4, Na2[Pb(OH)4] and (NH4)2[Pb(CH3COO)4]
Answer: D
💡 Solution & Explanation
(Hot solution) PbCl + K2CrO4 (A) PbCrO + 2KCl PbCrO4 + 4NaOH (excess) 4 (B) Na Pb OH + Na2CrO4 PbSO4 + 4CH3COONH4 3 4 (X) NH [Pb CH COO ] + (NH4)2SO4
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