Correct answer: 6.   2 2 4 Roasting Pb S PbO SO     Change of oxidation state = (4 – (–2)) = 6

See image | AITS & Test Series — Chem-Mantra

AITS & Test SerieshardNUMERICAL

Question

See image

Answer: 6

💡 Solution & Explanation

  2 2 4 Roasting Pb S PbO SO     Change of oxidation state = (4 – (–2)) = 6

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry