A 300 mL bottle of soft drink has 0.2 M CO2 dis — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

Number of mole of CO2 = M × V × 10–3 = 0.2 × 300 × 10–3 = 0.06 mole Volume of CO2 (at STP) = 0.06 × 22.7 = 1.362 L = 1362 mL