Match Column I with Column II: (Consider atmospheric pressure equal to 1 atm and density of mercury — States of Matter and Gaseous State Chemistry Question
Question
Match Column I with Column II: (Consider atmospheric pressure equal to 1 atm and density of mercury = 13.6 g/ml, if needed) Column I (Pressure exerted by gas in figures): (A) 1.50 atm (B) 1.75 atm (C) 0.50 atm Column II (Manometer diagrams): (P) Manometer showing a mercury column difference of 38 cm where the open arm is higher. (Q) Closed bulb with a piston loaded with 57 cm Hg. (R) Manometer with open arm having a vacuum above mercury, showing a height difference of 38 cm. (S) Manometer with glycerine column of height 1.9 m.
💡 Solution & Explanation
1 atm = 76 cm Hg. (P) Open arm higher by 38 cm: $P_{gas}=76+38=114$ cm Hg $=1.50$ atm → A. (Q) Closed piston loaded with 57 cm Hg: $P_{gas}=76+57=133$ cm Hg $=1.75$ atm → B. (R) Open arm vacuum above mercury, height 38 cm: $P_{gas}=38/76=0.50$ atm → C. (S) Glycerine column 1.9 m: equivalent Hg height $=1.9\times(2.72/13.6)\text{ m}=38$ cm; $P_{gas}=76+38=114$ cm Hg $=1.50$ atm → A.