How many pairs are, in which first species has lower ionisation energy than second species: (i) N an β Periodic Table and Periodicity Chemistry Question
Question
How many pairs are, in which first species has lower ionisation energy than second species: (i) N and O (ii) Br and K (iii) Be and B (iv) I and I- (v) Li and Li+ (vi) O and S (vii) Ba and Sr
Answer: 2
π‘ Solution & Explanation
Step 1: Identify which elements exist in the liquid state at room temperature. Mercury (Hg) is the liquid metal, and Bromine (Br) is the liquid non-metal. Step 2: Find the atomic numbers of these elements. Mercury has Z=80 and Bromine has Z=35. Step 3: The question asks for the metallic element's atomic number followed by the non-metallic element's atomic number, which yields the pair 80 and 35.
π¬Ask on WhatsApp β
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp β gets answered in minutes