See image | AITS & Test Series — Chem-Mantra

AITS & Test SerieshardNUMERICAL

Question

See image

Answer: 01690.00

💡 Solution & Explanation

Tf = Kf  m = Kf w 1000 M W   or, 0 – (-6) = 1.86  1  1000 W On solving W = 310 g  Mass of ice = 2000 – 310 = 1690.00 g

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET