The force of attraction on electron by the nucleus is directly ∝ — Atomic Structure Chemistry Question

💡 Solution & Explanation

The Coulombic force of attraction between the positive nucleus and the revolving electron is F = k * Z * e^2 / r^2. Since the Bohr radius r is ∝ n^2 / Z, we have r^2 ∝ n^4 / Z^2. Substituting this into the force expression: F is ∝ Z / (n^4 / Z^2) = Z^3 / n^4.