JEE Mains Chemistry Past PapershardMCQ SINGLE

For the reaction, N2O4 2NO2, graph is plotted as shown below. Identify correct statements. A. StandaJEE Mains Chemistry Past Papers Chemistry Question

Question

For the reaction, N2O4 2NO2, graph is plotted as shown below. Identify correct statements. A. Standard free energy change for the reaction is –5.40 kJ mol –1. B. As AG in graph is positive, N2O4 will not dissociate into NO2 at all. C. Reverse reaction will go to completion. D. When 1 mole of N2O4 changes into equilibrium mixture, value of G = –0.84 kJ mol –1 E. When 2 mole of NO2, changes into equilibrium mixture, G for equilibrium mixture is –6.24 kJ mol –1. E. When 2 mole of NO2, changes into equilibrium mixture, G for equilibrium mixture is –6.24 kJ mol –1. G kJ mol –1 B 5.40 A 0.2 0.4 0.6 0.8 E 0.84 Constant p, T Fraction of N2O4 dissociated Choose the correct answer from the options given below : (A) D and E only (B) C and E only (C) A and D only (D) B and C only

Answer: A

💡 Solution & Explanation

G kJ mol –1 B 5.40 A 0.2 0.4 0.6 0.8 E 0.84 Constant p, Fraction of N2O4 dissociated (A) rG° = G°B – G°A = +ve (B) rG° = +ve, N2O4 will partially dissociates into NO2. (C) For reverse reaction It is partially completed as there is equilibrium at E. (D) For 1 mole N2O4; rG° = – 0.84 kJ mol –1 (E) For 2 mole NO2 ; G° = – 5.4 – 0.84 = – 6.24 kJ mol –1. ALLEN 7 JEE-Main Exam Session-1 (January 2026)/21- 

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Mains Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry