Consider the following reaction approaching equilibrium at 27ºC and 1 atm pressure KF = 103 Kb = 102 — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

Keq = 3 b f 0 K K   = 10 Gº = –RT n keq = – 8.3 × 300 n (10) = – 8.3 × 300 × 2.3 = – 5.72 × 103 J mol–1 = – 5.72 KJ mol–1  6 KJ mol–1 | JEE(Main) 2023 | DATE : 29-01-2023 (SHIFT-1) | PAPER-1 | OFFICIAL PAPER | CHEMISTRY PAGE # 11