Some amount of dichloromethane (CH2Cl2) is added to 671.141 mL of chloroform (CHCl3) to prepare 2.6 β JEE Mains Chemistry Past Papers Chemistry Question
Question
Some amount of dichloromethane (CH2Cl2) is added to 671.141 mL of chloroform (CHCl3) to prepare 2.6 Γ 10β3 M
Answer: .
π‘ Solution & Explanation
Molarity = V M W W ο΄ ο΄ 2.6 Γ 10β3 = . 85 W ο΄ ο΄ 141 . 85 6 . W ο΄ ο΄ ο΄ ο½ ο = 0.148 g Conc. of DCM (in ppm) = 10 . 49 . 148 . ο΄ ο΄ = 148 ppm
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