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Some amount of dichloromethane (CH2Cl2) is added to 671.141 mL of chloroform (CHCl3) to prepare 2.6 — JEE Mains Chemistry Past Papers Chemistry Question

Question

Some amount of dichloromethane (CH2Cl2) is added to 671.141 mL of chloroform (CHCl3) to prepare 2.6 × 10–3 M

Answer: .

💡 Solution & Explanation

Molarity = V M W W   2.6 × 10–3 = . 85 W   141 . 85 6 . W      = 0.148 g Conc. of DCM (in ppm) = 10 . 49 . 148 .   = 148 ppm

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