On adding KI to a metal salt solution, no precipitate was observed but the salt solution gives yello β Qualitative and Quantitative Analysis Chemistry Question
Question
On adding KI to a metal salt solution, no precipitate was observed but the salt solution gives yellow precipitate with K2CrO4 in the presence of CH3COOH. Then the salt is :
π‘ Solution & Explanation
Step 1: The absence of a precipitate upon adding KI rules out Pb2+ and Ag+, as they form highly insoluble iodides (yellow PbI2 and pale yellow AgI). Step 2: The formation of a yellow precipitate with K2CrO4 in the presence of acetic acid (CH3COOH) is characteristic of barium chromate (BaCrO4), which is insoluble in weak acids, whereas strontium chromate (SrCrO4) is soluble. Step 3: This identifies the cation as Ba2+, meaning the starting salt is BaCl2, corresponding to option (d).