See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Molecular mass of 2 4 A B 100    2A 4B 2A 4B 100, 5 given 2A     A 10 A 10,B 20, 1: 2 B 20     AITS-PT-I (Paper-2)-PCM(Sol.)-JEE(Advanced)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 11    2 4 2 2 A B g A g 2B g 1 2      At 10 min. V.D. = 25 Molecular mass = 50 100 50 1 2   1 2    2 1 %B by mole 100 50% 2      2 1 %A by mole 100 25% 4    At t = 20 min. 100 40 1 2  