See image β AITS & Test Series Chemistry Question
Question
See image

Answer: 00937.30
π‘ Solution & Explanation
Let the electron be boosted to nth level, then Number of spectral lines = οο½ ο ο½ ο₯ ο₯ n n 1 15 . Given, Or ο ο 1 n 1 n 15 2 ο ο΄ ο½ ο n = 6 AITS-FT-VII-(Paper-1)-PCM(Sol.)-JEE(Advanced)/19 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 8 Thus electron is boosted upto 6th energy level from ground state. Therefore H 2 2 1 1 1 35 R 109737 36 n 1 ο© οΉ ο½ ο ο½ ο΄ οͺ οΊ ο¬ ο« ο» ο¬ = 9.373 ο΄ 10ο6 cm = 937.3 Γ
π¬Ask on WhatsApp β
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp β gets answered in minutes