According to MO theory, number of species/ions from the following having identical bond order is____ — Chemical Bonding Chemistry Question

💡 Solution & Explanation

**Step 1: Recall the bond order formula** Bond order = (Number of bonding electrons - Number of antibonding electrons) / 2 **Step 2: Determine electron configurations for each species** - CN⁻: Total electrons = 6 + 7 + 1 = 14 electrons - NO⁺: Total electrons = 7 + 8 - 1 = 14 electrons - O₂: Total electrons = 8 + 8 = 16 electrons - O₂⁺: Total electrons = 16 - 1 = 15 electrons - O₂²⁺: Total electrons = 16 - 2 = 14 electrons **Step 3: Apply MO theory and calculate bond orders** **CN⁻ (14 e⁻):** σ1s² σ*1s² σ2s² σ*2s² π2p⁴ σ2p² - Bond order = (10 - 4) / 2 = **3** **NO⁺ (14 e⁻):** σ1s² σ*1s² σ2s² σ*2s² π2p⁴ σ2p² - Bond order = (10 - 4) / 2 = **3** **O₂ (16 e⁻):** σ1s² σ*1s² σ2s² σ*2s² σ2p² π2p⁴ π*2p² - Bond order = (10 - 6) / 2 = **2** **O₂⁺ (15 e⁻):** σ1s² σ*1s² σ2s² σ*2s² σ2p² π2p⁴ π*2p¹ - Bond order = (10 - 5) / 2 = **2.5** **O₂²⁺ (14 e⁻):** σ1s² σ*1s² σ2s