XeF4 reacts with SbF5 to form [XeFm]n+ [SbFy]z– m + n + y + z = ______________ — JEE Mains Chemistry Past Papers Chemistry Question
Question
XeF4 reacts with SbF5 to form [XeFm]n+ [SbFy]z– m + n + y + z = ______________
Answer: .
💡 Solution & Explanation
XeF4 + SbF5 [XeF3] [SbF6]– m = 3 p = 6 n = 1 q = +1 m + n + p + q = 3 + 1 + 6 + 1 = 11
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