The radius of the hydrogen atom in its ground state is 5.3 × 10^-11 m. After collision with an electron, it is found to have a radius of 21.2 × 10^-11 m. The principal quantum number of final state of

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The radius of the hydrogen atom in its ground state is 5.3 × 10^-11 m. After collision with an electron, it is found to have a radius of 21.2 × 10^-11 m. The principal quantum number of final state of the atom is

Prashant Kotian · Accepted Answer

Correct answer: A. r_n = r_1 × n². r_n/r_1 = 21.2/5.3 = 4 => n² = 4 => n = 2.

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