See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

   XY g X g Y g Equi. 1 0 0 Equi. 1 1 1 1 1 Equi. pressure P P P 1 1 1                                 P P. P 1 1 K 1 P 1                          2 P 2 K .P 1      2 P 2 1/ 3 K 1 9 1 P 9 8 8 1 1 3            2 2 P K 100 10