The equation of state for a gas is P(V - nb) = nRT, where b and R are constants. If the pressure and β States of Matter and Gaseous State Chemistry Question
Question
The equation of state for a gas is P(V - nb) = nRT, where b and R are constants. If the pressure and temperature are such that Vm = 10 b, what is the compressibility factor of gas in this condition?
Answer: A
π‘ Solution & Explanation
for 1 mole, the equation is p(vm - b) = rt. the compressibility factor z = pvm/rt. from the equation, p/rt = 1 / (vm - b). thus, z = vm / (vm - b). substituting vm = 10b: z = 10b / (10b - b) = 10b / 9b = 10/9.
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