See image — AITS & Test Series Chemistry Question
Question
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Answer: 0.40
💡 Solution & Explanation
N2O5 (g) 2 NO2 (g) + 2 1 O2 (g) Initially : 600 torr — — AITS-FT-I (Paper-1)-PCM(Sol.)-JEE(Advanced)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 7 At equilibrium: (600 – p) torr 2p torr 2 p torr Total press is 2 p 3 600 torr 600 + 2 p 3 = 960 or 2 p 3 = 360 or p = 240 torr fraction of N2O5 (g) decomposed = 600 240 = 0.4
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