The coloured salt P was warmed with NaOH solution and colourless gas Q was evolved and a coloured solution R was produced. The colour of salt P was different from that of solution 'R'. On adding BaCl2

Question

The coloured salt P was warmed with NaOH solution and colourless gas Q was evolved and a coloured solution R was produced. The colour of salt P was different from that of solution 'R'. On adding BaCl2 to 'R', a coloured PPT was obtained. Then the correct formula for salt P is

Prashant Kotian · Accepted Answer

Correct answer: B. de = (B sin ) dx x sin  L 2 0 e B sin xdx    e = 2 2 1B L sin 2   SECTION – B

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