See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

 2 2 ii H O / OH 2 4 H CrO       2 2 2 4 i P/Br ii H O iii KOH aq. iv conc. H SO /   B H i Ph C Me CH2  A Ph C H Me CH2 OH    B chiral   C Ph C H Me COOH  D O C C C O O Ph Me Ph Me O  E O H OH So, x = 9, y = 2, z = 1.