The mass of ammonia in grams produced when 2.8 kg of dinitrogen quantitatively reacts with 1 kg of d — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

Mole of N2 = 2800 = 100 & Mole of H2 = 1000 = 500 N2(g) + 3H2(g)  2NH3(g) Initial mole 500 Limiting reagent is N2 Final mole 0 500 – 300 200 Mass of NH3 formed = 200 × 17 = 3400 gram