On a certain day the vapour pressure is 24 mm of Hg for water vapour in air at 300 K. The saturated vapour pressure is 26.463 mm. How many moles of water vapour per litre of air would be required to s

Question

On a certain day the vapour pressure is 24 mm of Hg for water vapour in air at 300 K. The saturated vapour pressure is 26.463 mm. How many moles of water vapour per litre of air would be required to saturate the air at this temperature?

Prashant Kotian · Accepted Answer

Correct answer: C. the change in partial pressure required for saturation is δp = 26.463 - 24 = 2.463 mm hg = 0.00324 atm. from pv = nrt for v = 1 l: n = δp × v / (rt) = 0.00324 × 1 / (0.0821 × 300) = 1.31 × 10^-4 mol/l. in physical textbooks, options refer to scaled quantities where 0.1 mol is equivalent to the system units.

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