Consider the following compounds : (i) IF5 (ii) ClI4^- (iii) XeO2F2 (iv) NH2^- (v) BCl3 (vi) BeCl2 ( β Chemical Bonding Chemistry Question
Question
Consider the following compounds : (i) IF5 (ii) ClI4^- (iii) XeO2F2 (iv) NH2^- (v) BCl3 (vi) BeCl2 (vii) AsCl4^+ (viii) B(OH)3 (ix) NO2^- (x) ClO2^+ Then calculate value of "x + y - z", here, x, y and z are total number of compounds in given compounds in which central atom used their all three p-orbitals, only two p-orbitals and only one p-orbital in hybridisation respectively.
π‘ Solution & Explanation
Step 1: Gases that are highly polar or react with water to ionize cannot be collected over water because they dissolve in it completely. Step 2: HCl is an extremely polar covalent gas that dissociates completely into hydronium and chloride ions when exposed to water. Step 3: Due to this exceptional solubility, HCl gas is never collected over water.