See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

CF CH O CH CH O 3 2 3 2 3 2 (1) (2) (P) CH CH Br       In reaction 2nd Nucleophile is stronger. (Q) (Alkene) (1) 2 5 (CH ) CBr/ 3 3 C H O   (2) (CH ) CHCH Br/ 3 2 2   (Alkene) In reaction 1st 3º alkyl halide 1 > 2 (R) In reaction 1st stable carbocation is formed CH2  (Cyclopropyl methyl C+) 1 > 2 (S) In reaction 1st reagent in HI. HI is more ionised, gives sufficient concentration of H+ ion and I+ is a good Nucleophile also. > 2 AITS-FT-I-PCM(Sol.)-JEE(Main)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 12