The reaction of H N B Cl (A) with LiBH in tetrahydrofuran gives inorganic benzene (B). Furthur, the reaction of (A) with (C) leads to H N B (Me) . Compounds (B) and (C) respectively, are: 3 3 3 3 4 3

Question

The reaction of H N B Cl (A) with LiBH in tetrahydrofuran gives inorganic benzene (B). Furthur, the reaction of (A) with (C) leads to H N B (Me) . Compounds (B) and (C) respectively, are: 3 3 3 3 4 3 3 3 3 3 3 3 3 4 3 3 6 3 3 3 3 3 3 3 3 3 3 3 3 3 6 3

(A) Boron nitride, MeBr
(B) Diborane, MeMgBr
(C) Borazine, MeBr
(D) Borazine, MeMgBr

Prashant Kotian · Accepted Answer

Correct answer: D) BORAZINE, MEMGBR. B N H Cl + LiBH → B N H + LiCl + BCl B N H Cl + 3CH MgBr → B N H (CH ) + 3MgBrCl So, we can say that, B is B N H C is CH MgBr

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