Correct answer: 4. 2 2 2 2 SO SO x SO X SO X M 4r r 64 r M r M    X M 4  

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AITS & Test SerieshardNUMERICAL

Question

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Answer: 4

💡 Solution & Explanation

2 2 2 2 SO SO x SO X SO X M 4r r 64 r M r M    X M 4  

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