The dissociation energy of is 429.0 kJ/mol. If is dissociated by illumination with radiation of wavelength 270.0 nm, what percentage of radiant energy will be converted into kinetic energy? (h = 6.6 ×

Question

The dissociation energy of $H_2$ is 429.0 kJ/mol. If $H_2$ is dissociated by illumination with radiation of wavelength 270.0 nm, what percentage of radiant energy will be converted into kinetic energy? (h = 6.6 × 10^-34 J·s, NA = 6 × 10^23)

Prashant Kotian · Accepted Answer

Correct answer: B. E per mole = hcNA/λ = (6.6 × 10^-34 × 3 × 10^8 × 6 × 10^23) / (270 × 10^-9) = 440 kJ/mol. K.E. = 440 - 429 = 11 kJ/mol. % = (11/440) × 100% = 2.5%.

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