A volume of 100 ml of 0.5 N- solution is neutralized with 200 ml of 0.2 M- in a constant pressure ca — Thermodynamics and Thermochemistry Chemistry Question
Question
A volume of 100 ml of 0.5 N-$H_2SO_4$ solution is neutralized with 200 ml of 0.2 M-$NH_4OH$ in a constant pressure calorimeter which resulted 1.4°C rise in temperature. The heat capacity of the calorimeter system is 1.5 kJ/°C. Some useful thermochemical equations are: $HCl$ + $NaOH$ -> $NaCl$ + $H_2O$ + 57 kJ; CH3COOH + $NH_4OH$ -> CH3COONH4 + $H_2O$ + 48.1 kJ. Which of the following statements are correct?
💡 Solution & Explanation
q = 1.5 * 1.4 = 2.1 kJ. $NH_4OH$ (limiting) = 0.04 mol. δ H_neut = -2.1/0.04 = -52.5 kJ/mol (A correct). δ H_diss($NH_4OH$) = -52.5 - (-57) = +4.5 kJ/mol (B correct). δ H_diss(CH3COOH) = -48.1 - (-57 + 4.5) = -48.1 + 52.5 = +4.6 kJ/mol (C correct). 2$H_2O$ -> 2H+ + 2OH-: δ H = 2 * 57 = 114 kJ (D correct).