A2 ⇌ 2A; K1 = x atm Initial partial pressure: 1 atm, 0 Equ. Partial pressure: 1-(x+z), 0 B2 ⇌ 2B; K2 — AITS & Test Series Chemistry Question
Question
A2 ⇌ 2A; K1 = x atm Initial partial pressure: 1 atm, 0 Equ. Partial pressure: 1-(x+z), 0 B2 ⇌ 2B; K2 = y atm Initial partial pressure: 1 atm, 0 Eq. partial pressure: 1-(y+z), 2y A2 + B2 ⇌ 2AB; K3 = 2 Initial partial pressure: 1, 1, 0 Equ.partialpressure: 1-(x+z), 1-(y+z), (2z=0.5) Find K2/K1

Answer: A
💡 Solution & Explanation
(P) [Cr(H2O)4Br2]+ Paramagnetic, d2sp3, show geometrical isomerism (Q) [Cu(NH2CH2CH2NH2] (CN)2Cl]2– Paramagnetic, sp3d2, show Geometrical isomerism (R) [Pt(ox)2]2– Diamagnetic, dsp2 (S) [Fe(OH)4]–Paramagnetic, sp3
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes