A2 ⇌ 2A; K1 = x atm Initial partial pressure: 1 atm, 0 Equ. Partial pressure: 1-(x+z), 0 B2 ⇌ 2B; K2 = y atm Initial partial pressure: 1 atm, 0 Eq. partial pressure: 1-(y+z), 2y A2 + B2 ⇌ 2AB; K3 = 2

Question

A2 ⇌ 2A; K1 = x atm
Initial partial pressure: 1 atm, 0
Equ. Partial pressure: 1-(x+z), 0

B2 ⇌ 2B; K2 = y atm
Initial partial pressure: 1 atm, 0
Eq. partial pressure: 1-(y+z), 2y

A2 + B2 ⇌ 2AB; K3 = 2
Initial partial pressure: 1, 1, 0
Equ.partialpressure: 1-(x+z), 1-(y+z), (2z=0.5)

Find K2/K1

Prashant Kotian · Accepted Answer

Correct answer: A. (P) [Cr(H2O)4Br2]+ Paramagnetic, d2sp3, show geometrical isomerism (Q) [Cu(NH2CH2CH2NH2] (CN)2Cl]2– Paramagnetic, sp3d2, show Geometrical isomerism (R) [Pt(ox)2]2–  Diamagnetic, dsp2 (S) [Fe(OH)4]–Paramagnetic, sp3

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