X2(g) + Y2(g) 2Z(g) X2(g) and Y2(g) are added to a 1 L flask and it is found that the system attains the above equilibrium at T(K) with the number of moles of X2(g) , Y2(g) and Z(g) being 3, 3 and 9 m

Question

X2(g) + Y2(g) 2Z(g) X2(g) and Y2(g) are added to a 1 L flask and it is found that the system attains the above equilibrium at T(K) with the number of moles of X2(g) , Y2(g) and Z(g) being 3, 3 and 9 mol respectively (equilibrium moles). Under this conditions of equilibrium, 10 mol of Z(g) is added to the flask and the temperature is maintained at T(K). Then the number of moles of Z(g) in the flask when the new equilibrium is established is ______. (Nearest integer).

Prashant Kotian · Accepted Answer

Correct answer: .. X2(g) + Y2(g) 2Z (g) KC = (9) 3 3   Now 10 moles of Z are added then reaction will move in backward direction. X2(g) + Y2(g) 2Z (g) 3 + X 3 + X 19–2X KC = (19 2X) (3 X)(3 X)     2X 3 X    19 – 2X = 9 + 3X 10 = 5X X = 2 At equilibrium  moles of Z = 19 – 2 × 2 = 15 moles

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