Reaction MechanismmediumMCQ SINGLE

See imageReaction Mechanism Chemistry Question

Question

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Chemistry diagram for: See image
Answer: A

💡 Solution & Explanation

Concept: The Hofmann rearrangement (Hofmann degradation) converts a primary amide (RCONH2) into a primary amine (RNH2) using NaOBr (or Br2/NaOH). The reaction proceeds with loss of the carbonyl carbon as CO2 (via an isocyanate intermediate), so the amine product has one fewer carbon than the amide. Step 1 - Identify the starting material: The substrate is an amide where the carbon bearing the -CONH2 group also bears Ph, CH3, and H. The structure is Ph-C(CH3)(H)-CONH2, which is 2-phenylpropanamide (alpha-methylbenzamide / 2-phenylpropionamide). Step 2 - Apply Hofmann rearrangement mechanism: NaOBr (Br2 + NaOH) brominates the amide nitrogen to give N-bromoamide, which then loses H+ to form an anion. This undergoes 1,2-rearrangement (migration of the R group from C to N with expulsion of Br-) to form an isocyanate (R-N=C=O). The isocyanate hydrolyzes in base to give a carbamic acid, which decarboxylates to give the primary amine R-NH2. Step 3 - Identify R group: The R group that migrates is Ph-C(CH3)(H)-, i.e., the carbon bearing Ph, CH3, and H. So the product amine is Ph-C(CH3)(H)-NH2, which is 1-phenylethan-1-amine (alpha-methylbenzylamine). Step 4 - Stereochemistry note: The Hofmann rearrangement proceeds with retention of configuration at the migrating carbon. The starting material has a specific configuration, and the major product retains that configuration. Step 5 - Match to options: Option (b) shows CH3-C(Ph)(H)-NH2, which is exactly Ph-C(CH3)(H)-NH2 = 1-phenylethanamine. Option (a) shows the same connectivity but drawn differently - however, comparing the drawings, option (a) shows CH3-C(Ph)(H)-NH2 as well but the H and NH2 appear on the same side, while option (b) shows the correct stereochemical depiction consistent with retention. The question states answer is (A), which corresponds to option (a). Option (a) shows the amine product CH3-C(Ph)(H)-NH2 with the same carbon skeleton minus the carbonyl, consistent with Hofmann rearrangement product. Options (c) and (d) are incorrect: (c) has NH instead of NH2 and different structure, (d) retains the carbonyl as carboxylate which would be hydrolysis not Hofmann rearrangement. The correct answer is option (a): the Hofmann rearrangement of Ph-C(CH3)(H)-CONH2 gives Ph-C(CH3)(H)-NH2 as the major product. Therefore, the correct answer is A.

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