When N2O5 is heated at certain temperature, it dissociates as N2O5(g) ⇌ N2O3(g) + O2(g); Kc = 2.5. At the same time N2O3 also decomposes as: N2O3(g) ⇌ N2O(g) + O2(g). If initially 4.0 moles of N2O5 ar

Question

When N2O5 is heated at certain temperature, it dissociates as N2O5(g) ⇌ N2O3(g) + O2(g); Kc = 2.5. At the same time N2O3 also decomposes as: N2O3(g) ⇌ N2O(g) + O2(g). If initially 4.0 moles of N2O5 are taken in 1.0 litre flask and allowed to dissociation, concentration of O2 at equilibrium is 2.5M. Equilibrium concentration of N2O5 is:

Prashant Kotian · Accepted Answer

Correct answer: D. 2 5 2 3 2 x y 4 x x y N O N O O      2 3 2 2 y y x x y N O N O O     2 [O ]=x+y = 2.5  (x y)(x y) and 2.5 = 4 x     x

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