Ans. (B) Sol. (A) BCl3 - Even electron molecules SF6 - Expended octet molecules (B) NO - Odd electro — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

(A) BCl3 - Even electron molecules SF6 - Expended octet molecules (B) NO - Odd electron molecules H2SO4 - Expanded octet (C) SF6 – Even electron molecules H2SO4 – Expanded octet (D) BCl3 – Even electron molecules NO – odd electron molecules 2.. Ans. (C) Sol. N2(g) + 3H2(g) ⇌ 2NH3(g) w2 = 20 g 5 g n = 28 2 Stoichiometric amount N2 = 20/80 = 28 H2 = 5/2 3 = 6  N2 is the limiting reagent  n(NH3) = 2 × n(N2) = 2 × 28 = 1.42 | JEE MAIN-2022 | DATE : 29-07-2022 (SHIFT-1) | PAPER-1 | | CHEMISTRY PAGE # 2