A metal having atomic mass 60.22 g/mole crystallizes in ABCABC.... type packing. The density of each metal atom if the edge length of unit cell is 10 Å, is (Na = 6.022 × 10^23)

Question

Prashant Kotian · Accepted Answer

Correct answer: C. For FCC lattice, Z = 4. a = 10 Å. Radius of atom r = a × √2 / 4 = 10 × 1.414 / 4 = 3.535 Å. Volume of one atom = 4/3 × π × r³ = 4/3 × 3.1416 × (3.535 × 10^-8)³ = 1.85 × 10^-22 cm³. Mass of one atom = M / Na = 60.22 / 6.022 × 10^23 = 10^-22 g. Density of each atom = Mass / Volume = 10^-22 / 1.85 × 10^-22 = 0.54 g/cm³.

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