See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

sin 45 =  sin r  r = 30 From BQR and CSR BQ BR SC RC   RC h 3 BR        i = 45+ r = 75 So, QM tan15 MR  , so MR = 12 cm So, BR = 15 cm and RC = 5 cm So, h = 1cm 45 45 h B A C 45 45 Q S R P T  i i i i M AITS-CRT-I-PCM(Sol.)-JEE(Main)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 8 Chemistry PART – B SECTION – A