NaCl(solid) + K2Cr2O7 (solid) + conc. H2SO4 -Warm-> Reddish brown fumes of 'X'. The oxidation state β Redox Reactions and Volumetric Analysis Chemistry Question
Question
NaCl(solid) + K2Cr2O7 (solid) + conc. H2SO4 -Warm-> Reddish brown fumes of 'X'. The oxidation state of central atom in compound 'X' is :
Answer: A
π‘ Solution & Explanation
Step 1: Boron trichloride (BCl3) undergoes rapid hydrolysis at room temperature to yield orthoboric acid (H3BO3) and hydrochloric acid (HCl). Step 2: The product containing the boron atom is boric acid (H3BO3), which has the "-ic" suffix. Step 3: Therefore, the boron-containing product is an oxyacid with an "-ic" suffix, matching option (a).
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